Factoring
Given a quadratic equation : ax2 + bx + c
Can be factored into (mx+p)(nx+q)
=mnx2 + mxq + pnx + pq
=(mn)x2 + (mq+pn)x+pq
=mn=a, mq+pn=b, pq=c
General Steps to solve by factoring
- Create a factor for all factor pairs of c
- A factor pairs is just two numbers that multiply and give you ‘c’
- Out o all the factor pairs from step 1, look for the fair (if it exist) that add up to b
- Note : if the pair does not exist, you must either complete the square or use the quadratic formula.
- Insert the pair you found in step 2 into two binomials
- Solve each binomial for zero to get the solutions of the quadratic equation.
If ax2 + bx + c then (x + h)(x + k)
If ax2 + bx –c or ax2 +bx-c then (x – h)(x + k)
If ax2 – bx +c then (x - h)(x – k)
Example 1 : x2 + 5x + 6 = 0
This can be factored into (x + 2)(x + 3) = 0.
So the solution must be x = -2 and x = -3.
Can be factored into (mx+p)(nx+q)
=mnx2 + mxq + pnx + pq
=(mn)x2 + (mq+pn)x+pq
=mn=a, mq+pn=b, pq=c
General Steps to solve by factoring
- Create a factor for all factor pairs of c
- A factor pairs is just two numbers that multiply and give you ‘c’
- Out o all the factor pairs from step 1, look for the fair (if it exist) that add up to b
- Note : if the pair does not exist, you must either complete the square or use the quadratic formula.
- Insert the pair you found in step 2 into two binomials
- Solve each binomial for zero to get the solutions of the quadratic equation.
If ax2 + bx + c then (x + h)(x + k)
If ax2 + bx –c or ax2 +bx-c then (x – h)(x + k)
If ax2 – bx +c then (x - h)(x – k)
Example 1 : x2 + 5x + 6 = 0
This can be factored into (x + 2)(x + 3) = 0.
So the solution must be x = -2 and x = -3.
Factoring
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